Advanced SQL Database Programmers Handbook by Donald K. Burleson, Joe Celko, John Paul Cook, Peter

By Donald K. Burleson, Joe Celko, John Paul Cook, Peter Gulutzan

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And likewise, few products reorder the execution based on table sizes. Consider this expression: (TABLE SmallTable1) UNION (TABLE BigTable) UNION (TABLE SmallTable2); It will probably merge SmallTable1 into BigTable, then merge SmallTable2 into that first result. com/oracle There are many reason that products lack UNION optimizations. First, UNIONs are not a common operation, so it is not worth the effort. And secondly, the order of execution becomes important if UNION and UNION ALL are mixed together: TABLE UNION TABLE UNION TABLE X Y ALL Z Is executed as (TABLE X UNION TABLE Y) UNION ALL TABLE Z and that is not the same as: TABLE X UNION (TABLE Y UNION ALL TABLE Z) Optimization of UNIONs is highly product-dependent, so you should experiment with it.

In good database model, each table has one and only one type of elements. That is, you don't have more than one Inventory table, more than one Personnel table, etc. com/oracle 31 But when the INCITS H2 (nee ANSI X3) Database Standards Committee added these operators, the model in the SQL-92 standard was to pair off the two tables on a row-per-row basis for set operations. (note: In SQL-92, we introduced the shorthand TABLE

for the query or subquery SELECT * FROM

, which lets us refer to a table as a whole without referring to its columns.

That is not a good idea when you are excluding documents. When you wanted to get rid "Smith" is does not follow that you also wanted to get rid of "Smithsonian" as well. For this example, Let you agree that equality is the right matching criteria, to keep the code simple. Put that solution aside for a minute and move on to the other part of the problem; finding documents that have all the words you have in your search list. key_word); This answer is wrong. It will pick documents with any search word, not all search words.

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